2(y+1)+1=1/3(6y+9)

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Solution for 2(y+1)+1=1/3(6y+9) equation: 



2(y+1)+1=1/3(6y+9)

We move all terms to the left:

2(y+1)+1-(1/3(6y+9))=0



Domain of the equation: 3(6y+9))!=0

y∈R



We multiply parentheses

2y-(1/3(6y+9))+2+1=0

We multiply all the terms by the denominator


2y*3(6y+9))-(1+2*3(6y+9))+1*3(6y+9))=0

We add all the numbers together, and all the variables

2y*3(6y+9))-(1+2*3(6y+9))+1*3(6y=0

Wy multiply elements

6y^2(6+18y^2(6=0

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