2(y+1)+2(4y/5)=62

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Solution for 2(y+1)+2(4y/5)=62 equation: 



2(y+1)+2(4y/5)=62

We move all terms to the left:

2(y+1)+2(4y/5)-(62)=0

We add all the numbers together, and all the variables

2(y+1)+2(+4y/5)-62=0

We multiply parentheses

2y+8y+2-62=0

We add all the numbers together, and all the variables

10y-60=0

We move all terms containing y to the left, all other terms to the right

10y=60

y=60/10

y=6

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