2(y+1)+4y=3(2y-1)+8

Solution for 2(y+1)+4y=3(2y-1)+8 equation:

Simplifying
2(y + 1) + 4y = 3(2y + -1) + 8

Reorder the terms:
2(1 + y) + 4y = 3(2y + -1) + 8
(1 * 2 + y * 2) + 4y = 3(2y + -1) + 8
(2 + 2y) + 4y = 3(2y + -1) + 8

Combine like terms: 2y + 4y = 6y
2 + 6y = 3(2y + -1) + 8

Reorder the terms:
2 + 6y = 3(-1 + 2y) + 8
2 + 6y = (-1 * 3 + 2y * 3) + 8
2 + 6y = (-3 + 6y) + 8

Reorder the terms:
2 + 6y = -3 + 8 + 6y

Combine like terms: -3 + 8 = 5
2 + 6y = 5 + 6y

Add '-6y' to each side of the equation.
2 + 6y + -6y = 5 + 6y + -6y

Combine like terms: 6y + -6y = 0
2 + 0 = 5 + 6y + -6y
2 = 5 + 6y + -6y

Combine like terms: 6y + -6y = 0
2 = 5 + 0
2 = 5

Solving
2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.