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2(y+1)+4y=3(2y-1-+8
We move all terms to the left:
2(y+1)+4y-(3(2y-1-+8)=0
We add all the numbers together, and all the variables
2(y+1)+4y-(3(+2y)=0
We add all the numbers together, and all the variables
4y+2(y+1)-(3(+2y)=0
We multiply parentheses
4y+2y-(3(+2y)+2=0
We add all the numbers together, and all the variables
6y-(3(+2y)+2=0
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