2(y+1)+4y=3(y-1)+7

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Solution for 2(y+1)+4y=3(y-1)+7 equation: 



2(y+1)+4y=3(y-1)+7

We move all terms to the left:

2(y+1)+4y-(3(y-1)+7)=0

We add all the numbers together, and all the variables

4y+2(y+1)-(3(y-1)+7)=0

We multiply parentheses

4y+2y-(3(y-1)+7)+2=0



We calculate terms in parentheses: -(3(y-1)+7), so:

3(y-1)+7

We multiply parentheses

3y-3+7

We add all the numbers together, and all the variables

3y+4

Back to the equation:

-(3y+4)



We add all the numbers together, and all the variables

6y-(3y+4)+2=0

We get rid of parentheses

6y-3y-4+2=0

We add all the numbers together, and all the variables

3y-2=0

We move all terms containing y to the left, all other terms to the right

3y=2

y=2/3

y=2/3

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