2(y+1)+7=3(y-2)+2y=

Solution for 2(y+1)+7=3(y-2)+2y= equation:

2(y+1)+7=3(y-2)+2y=

We move all terms to the left:

2(y+1)+7-(3(y-2)+2y)=0

We multiply parentheses

2y-(3(y-2)+2y)+2+7=0


We calculate terms in parentheses: -(3(y-2)+2y), so:

3(y-2)+2y

We add all the numbers together, and all the variables

2y+3(y-2)

We multiply parentheses

2y+3y-6

We add all the numbers together, and all the variables

5y-6

Back to the equation:

-(5y-6)


We add all the numbers together, and all the variables

2y-(5y-6)+9=0

We get rid of parentheses

2y-5y+6+9=0

We add all the numbers together, and all the variables

-3y+15=0

We move all terms containing y to the left, all other terms to the right

-3y=-15

y=-15/-3

y=+5