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2(y+1)+7=3(y-2)+2y=
We move all terms to the left:
2(y+1)+7-(3(y-2)+2y)=0
We multiply parentheses
2y-(3(y-2)+2y)+2+7=0
We calculate terms in parentheses: -(3(y-2)+2y), so:We add all the numbers together, and all the variables
3(y-2)+2y
We add all the numbers together, and all the variables
2y+3(y-2)
We multiply parentheses
2y+3y-6
We add all the numbers together, and all the variables
5y-6
Back to the equation:
-(5y-6)
2y-(5y-6)+9=0
We get rid of parentheses
2y-5y+6+9=0
We add all the numbers together, and all the variables
-3y+15=0
We move all terms containing y to the left, all other terms to the right
-3y=-15
y=-15/-3
y=+5
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