2(y+1)+7=3(y-2)=2y

Solution for 2(y+1)+7=3(y-2)=2y equation:

2(y+1)+7=3(y-2)=2y

We move all terms to the left:

2(y+1)+7-(3(y-2))=0

We multiply parentheses

2y-(3(y-2))+2+7=0


We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)


We add all the numbers together, and all the variables

2y-(3y-6)+9=0

We get rid of parentheses

2y-3y+6+9=0

We add all the numbers together, and all the variables

-1y+15=0

We move all terms containing y to the left, all other terms to the right

-y=-15

y=-15/-1

y=+15