2(y+1)-1(y-2)=2

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Solution for 2(y+1)-1(y-2)=2 equation: 


Simplifying
2(y + 1) + -1(y + -2) = 2

Reorder the terms:
2(1 + y) + -1(y + -2) = 2
(1 * 2 + y * 2) + -1(y + -2) = 2
(2 + 2y) + -1(y + -2) = 2

Reorder the terms:
2 + 2y + -1(-2 + y) = 2
2 + 2y + (-2 * -1 + y * -1) = 2
2 + 2y + (2 + -1y) = 2

Reorder the terms:
2 + 2 + 2y + -1y = 2

Combine like terms: 2 + 2 = 4
4 + 2y + -1y = 2

Combine like terms: 2y + -1y = 1y
4 + 1y = 2

Solving
4 + 1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1y = 2 + -4

Combine like terms: 4 + -4 = 0
0 + 1y = 2 + -4
1y = 2 + -4

Combine like terms: 2 + -4 = -2
1y = -2

Divide each side by '1'.
y = -2

Simplifying
y = -2

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