2(y+1)-3(y-1)=5-y

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Solution for 2(y+1)-3(y-1)=5-y equation: 


Simplifying
2(y + 1) + -3(y + -1) = 5 + -1y

Reorder the terms:
2(1 + y) + -3(y + -1) = 5 + -1y
(1 * 2 + y * 2) + -3(y + -1) = 5 + -1y
(2 + 2y) + -3(y + -1) = 5 + -1y

Reorder the terms:
2 + 2y + -3(-1 + y) = 5 + -1y
2 + 2y + (-1 * -3 + y * -3) = 5 + -1y
2 + 2y + (3 + -3y) = 5 + -1y

Reorder the terms:
2 + 3 + 2y + -3y = 5 + -1y

Combine like terms: 2 + 3 = 5
5 + 2y + -3y = 5 + -1y

Combine like terms: 2y + -3y = -1y
5 + -1y = 5 + -1y

Add '-5' to each side of the equation.
5 + -5 + -1y = 5 + -5 + -1y

Combine like terms: 5 + -5 = 0
0 + -1y = 5 + -5 + -1y
-1y = 5 + -5 + -1y

Combine like terms: 5 + -5 = 0
-1y = 0 + -1y
-1y = -1y

Add 'y' to each side of the equation.
-1y + y = -1y + y

Combine like terms: -1y + y = 0
0 = -1y + y

Combine like terms: -1y + y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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