2(y+1)-4(y+2)=

Solution for 2(y+1)-4(y+2)= equation:

Simplifying
2(y + 1) + -4(y + 2) = 0

Reorder the terms:
2(1 + y) + -4(y + 2) = 0
(1 * 2 + y * 2) + -4(y + 2) = 0
(2 + 2y) + -4(y + 2) = 0

Reorder the terms:
2 + 2y + -4(2 + y) = 0
2 + 2y + (2 * -4 + y * -4) = 0
2 + 2y + (-8 + -4y) = 0

Reorder the terms:
2 + -8 + 2y + -4y = 0

Combine like terms: 2 + -8 = -6
-6 + 2y + -4y = 0

Combine like terms: 2y + -4y = -2y
-6 + -2y = 0

Solving
-6 + -2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -2y = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -2y = 0 + 6
-2y = 0 + 6

Combine like terms: 0 + 6 = 6
-2y = 6

Divide each side by '-2'.
y = -3

Simplifying
y = -3