2(y+1)-4(y-2)=6y+10-8y

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Solution for 2(y+1)-4(y-2)=6y+10-8y equation: 



2(y+1)-4(y-2)=6y+10-8y

We move all terms to the left:

2(y+1)-4(y-2)-(6y+10-8y)=0

We add all the numbers together, and all the variables

2(y+1)-4(y-2)-(-2y+10)=0

We multiply parentheses

2y-4y-(-2y+10)+2+8=0

We get rid of parentheses

2y-4y+2y-10+2+8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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