2(y+1)48=3(2y-1)+8

Solution for 2(y+1)48=3(2y-1)+8 equation:

2(y+1)48=3(2y-1)+8

We move all terms to the left:

2(y+1)48-(3(2y-1)+8)=0

We multiply parentheses

96y-(3(2y-1)+8)+96=0


We calculate terms in parentheses: -(3(2y-1)+8), so:

3(2y-1)+8

We multiply parentheses

6y-3+8

We add all the numbers together, and all the variables

6y+5

Back to the equation:

-(6y+5)


We get rid of parentheses

96y-6y-5+96=0

We add all the numbers together, and all the variables

90y+91=0

We move all terms containing y to the left, all other terms to the right

90y=-91

y=-91/90

y=-1+1/90