2(y+1)=(y+3)

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Solution for 2(y+1)=(y+3) equation: 



2(y+1)=(y+3)

We move all terms to the left:

2(y+1)-((y+3))=0

We multiply parentheses

2y-((y+3))+2=0



We calculate terms in parentheses: -((y+3)), so:

(y+3)

We get rid of parentheses

y+3

Back to the equation:

-(y+3)



We get rid of parentheses

2y-y-3+2=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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