2(y+1)=3(y-2)+6

Solution for 2(y+1)=3(y-2)+6 equation:

Simplifying
2(y + 1) = 3(y + -2) + 6

Reorder the terms:
2(1 + y) = 3(y + -2) + 6
(1 * 2 + y * 2) = 3(y + -2) + 6
(2 + 2y) = 3(y + -2) + 6

Reorder the terms:
2 + 2y = 3(-2 + y) + 6
2 + 2y = (-2 * 3 + y * 3) + 6
2 + 2y = (-6 + 3y) + 6

Reorder the terms:
2 + 2y = -6 + 6 + 3y

Combine like terms: -6 + 6 = 0
2 + 2y = 0 + 3y
2 + 2y = 3y

Solving
2 + 2y = 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
2 + 2y + -3y = 3y + -3y

Combine like terms: 2y + -3y = -1y
2 + -1y = 3y + -3y

Combine like terms: 3y + -3y = 0
2 + -1y = 0

Add '-2' to each side of the equation.
2 + -2 + -1y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 0 + -2
-1y = 0 + -2

Combine like terms: 0 + -2 = -2
-1y = -2

Divide each side by '-1'.
y = 2

Simplifying
y = 2