2(y+1)=3(y-4)

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Solution for 2(y+1)=3(y-4) equation: 



2(y+1)=3(y-4)

We move all terms to the left:

2(y+1)-(3(y-4))=0

We multiply parentheses

2y-(3(y-4))+2=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We get rid of parentheses

2y-3y+12+2=0

We add all the numbers together, and all the variables

-1y+14=0

We move all terms containing y to the left, all other terms to the right

-y=-14

y=-14/-1

y=+14

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