2(y+1)=4y-2(y-1)

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Solution for 2(y+1)=4y-2(y-1) equation: 


Simplifying
2(y + 1) = 4y + -2(y + -1)

Reorder the terms:
2(1 + y) = 4y + -2(y + -1)
(1 * 2 + y * 2) = 4y + -2(y + -1)
(2 + 2y) = 4y + -2(y + -1)

Reorder the terms:
2 + 2y = 4y + -2(-1 + y)
2 + 2y = 4y + (-1 * -2 + y * -2)
2 + 2y = 4y + (2 + -2y)

Reorder the terms:
2 + 2y = 2 + 4y + -2y

Combine like terms: 4y + -2y = 2y
2 + 2y = 2 + 2y

Add '-2' to each side of the equation.
2 + -2 + 2y = 2 + -2 + 2y

Combine like terms: 2 + -2 = 0
0 + 2y = 2 + -2 + 2y
2y = 2 + -2 + 2y

Combine like terms: 2 + -2 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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