2(y+1)=4y-8

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Solution for 2(y+1)=4y-8 equation: 



2(y+1)=4y-8

We move all terms to the left:

2(y+1)-(4y-8)=0

We multiply parentheses

2y-(4y-8)+2=0

We get rid of parentheses

2y-4y+8+2=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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