2(y+1)=8y+42

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Solution for 2(y+1)=8y+42 equation: 



2(y+1)=8y+42

We move all terms to the left:

2(y+1)-(8y+42)=0

We multiply parentheses

2y-(8y+42)+2=0

We get rid of parentheses

2y-8y-42+2=0

We add all the numbers together, and all the variables

-6y-40=0

We move all terms containing y to the left, all other terms to the right

-6y=40

y=40/-6

y=-6+2/3

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