2(y+2)+3(y-4)=7

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Solution for 2(y+2)+3(y-4)=7 equation: 


Simplifying
2(y + 2) + 3(y + -4) = 7

Reorder the terms:
2(2 + y) + 3(y + -4) = 7
(2 * 2 + y * 2) + 3(y + -4) = 7
(4 + 2y) + 3(y + -4) = 7

Reorder the terms:
4 + 2y + 3(-4 + y) = 7
4 + 2y + (-4 * 3 + y * 3) = 7
4 + 2y + (-12 + 3y) = 7

Reorder the terms:
4 + -12 + 2y + 3y = 7

Combine like terms: 4 + -12 = -8
-8 + 2y + 3y = 7

Combine like terms: 2y + 3y = 5y
-8 + 5y = 7

Solving
-8 + 5y = 7

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 5y = 7 + 8

Combine like terms: -8 + 8 = 0
0 + 5y = 7 + 8
5y = 7 + 8

Combine like terms: 7 + 8 = 15
5y = 15

Divide each side by '5'.
y = 3

Simplifying
y = 3

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