2(y+2)+7=3(y+6)

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Solution for 2(y+2)+7=3(y+6) equation: 



2(y+2)+7=3(y+6)

We move all terms to the left:

2(y+2)+7-(3(y+6))=0

We multiply parentheses

2y-(3(y+6))+4+7=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We add all the numbers together, and all the variables

2y-(3y+18)+11=0

We get rid of parentheses

2y-3y-18+11=0

We add all the numbers together, and all the variables

-1y-7=0

We move all terms containing y to the left, all other terms to the right

-y=7

y=7/-1

y=-7

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