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2(y+2)+y=19-(2y+3
We move all terms to the left:
2(y+2)+y-(19-(2y+3)=0
We add all the numbers together, and all the variables
y+2(y+2)-(19-(2y+3)=0
We multiply parentheses
y+2y-(19-(2y+3)+4=0
We add all the numbers together, and all the variables
3y-(19-(2y+3)+4=0
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