2(y+2)+y=3(y-1)+6

Solution for 2(y+2)+y=3(y-1)+6 equation:

Simplifying
2(y + 2) + y = 3(y + -1) + 6

Reorder the terms:
2(2 + y) + y = 3(y + -1) + 6
(2 * 2 + y * 2) + y = 3(y + -1) + 6
(4 + 2y) + y = 3(y + -1) + 6

Combine like terms: 2y + y = 3y
4 + 3y = 3(y + -1) + 6

Reorder the terms:
4 + 3y = 3(-1 + y) + 6
4 + 3y = (-1 * 3 + y * 3) + 6
4 + 3y = (-3 + 3y) + 6

Reorder the terms:
4 + 3y = -3 + 6 + 3y

Combine like terms: -3 + 6 = 3
4 + 3y = 3 + 3y

Add '-3y' to each side of the equation.
4 + 3y + -3y = 3 + 3y + -3y

Combine like terms: 3y + -3y = 0
4 + 0 = 3 + 3y + -3y
4 = 3 + 3y + -3y

Combine like terms: 3y + -3y = 0
4 = 3 + 0
4 = 3

Solving
4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.