2(y+2)-26=2(-y-7)

Solution for 2(y+2)-26=2(-y-7) equation:

2(y+2)-26=2(-y-7)

We move all terms to the left:

2(y+2)-26-(2(-y-7))=0

We add all the numbers together, and all the variables

2(y+2)-(2(-1y-7))-26=0

We multiply parentheses

2y-(2(-1y-7))+4-26=0


We calculate terms in parentheses: -(2(-1y-7)), so:

2(-1y-7)

We multiply parentheses

-2y-14

Back to the equation:

-(-2y-14)


We add all the numbers together, and all the variables

2y-(-2y-14)-22=0

We get rid of parentheses

2y+2y+14-22=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2