2(y+2)-2=3(y-1)-2y

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Solution for 2(y+2)-2=3(y-1)-2y equation: 



2(y+2)-2=3(y-1)-2y

We move all terms to the left:

2(y+2)-2-(3(y-1)-2y)=0

We multiply parentheses

2y-(3(y-1)-2y)+4-2=0



We calculate terms in parentheses: -(3(y-1)-2y), so:

3(y-1)-2y

We add all the numbers together, and all the variables

-2y+3(y-1)

We multiply parentheses

-2y+3y-3

We add all the numbers together, and all the variables

y-3

Back to the equation:

-(y-3)



We add all the numbers together, and all the variables

2y-(y-3)+2=0

We get rid of parentheses

2y-y+3+2=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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