2(y+2)-4(y-2)=6y+12-8y

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Solution for 2(y+2)-4(y-2)=6y+12-8y equation:


Simplifying
2(y + 2) + -4(y + -2) = 6y + 12 + -8y

Reorder the terms:
2(2 + y) + -4(y + -2) = 6y + 12 + -8y
(2 * 2 + y * 2) + -4(y + -2) = 6y + 12 + -8y
(4 + 2y) + -4(y + -2) = 6y + 12 + -8y

Reorder the terms:
4 + 2y + -4(-2 + y) = 6y + 12 + -8y
4 + 2y + (-2 * -4 + y * -4) = 6y + 12 + -8y
4 + 2y + (8 + -4y) = 6y + 12 + -8y

Reorder the terms:
4 + 8 + 2y + -4y = 6y + 12 + -8y

Combine like terms: 4 + 8 = 12
12 + 2y + -4y = 6y + 12 + -8y

Combine like terms: 2y + -4y = -2y
12 + -2y = 6y + 12 + -8y

Reorder the terms:
12 + -2y = 12 + 6y + -8y

Combine like terms: 6y + -8y = -2y
12 + -2y = 12 + -2y

Add '-12' to each side of the equation.
12 + -12 + -2y = 12 + -12 + -2y

Combine like terms: 12 + -12 = 0
0 + -2y = 12 + -12 + -2y
-2y = 12 + -12 + -2y

Combine like terms: 12 + -12 = 0
-2y = 0 + -2y
-2y = -2y

Add '2y' to each side of the equation.
-2y + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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