2(y+2)-5=3(y+1)

Solution for 2(y+2)-5=3(y+1) equation:

2(y+2)-5=3(y+1)

We move all terms to the left:

2(y+2)-5-(3(y+1))=0

We multiply parentheses

2y-(3(y+1))+4-5=0


We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)


We add all the numbers together, and all the variables

2y-(3y+3)-1=0

We get rid of parentheses

2y-3y-3-1=0

We add all the numbers together, and all the variables

-1y-4=0

We move all terms containing y to the left, all other terms to the right

-y=4

y=4/-1

y=-4