2(y+2)-y=3(y+1)+9

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Solution for 2(y+2)-y=3(y+1)+9 equation:



2(y+2)-y=3(y+1)+9
We move all terms to the left:
2(y+2)-y-(3(y+1)+9)=0
We add all the numbers together, and all the variables
-1y+2(y+2)-(3(y+1)+9)=0
We multiply parentheses
-1y+2y-(3(y+1)+9)+4=0
We calculate terms in parentheses: -(3(y+1)+9), so:
3(y+1)+9
We multiply parentheses
3y+3+9
We add all the numbers together, and all the variables
3y+12
Back to the equation:
-(3y+12)
We add all the numbers together, and all the variables
y-(3y+12)+4=0
We get rid of parentheses
y-3y-12+4=0
We add all the numbers together, and all the variables
-2y-8=0
We move all terms containing y to the left, all other terms to the right
-2y=8
y=8/-2
y=-4

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