2(y+2)-y=3(y+1)+9

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Solution for 2(y+2)-y=3(y+1)+9 equation: 



2(y+2)-y=3(y+1)+9

We move all terms to the left:

2(y+2)-y-(3(y+1)+9)=0

We add all the numbers together, and all the variables

-1y+2(y+2)-(3(y+1)+9)=0

We multiply parentheses

-1y+2y-(3(y+1)+9)+4=0



We calculate terms in parentheses: -(3(y+1)+9), so:

3(y+1)+9

We multiply parentheses

3y+3+9

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

y-(3y+12)+4=0

We get rid of parentheses

y-3y-12+4=0

We add all the numbers together, and all the variables

-2y-8=0

We move all terms containing y to the left, all other terms to the right

-2y=8

y=8/-2

y=-4

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