2(y+2)=3(y-1)+9

Solution for 2(y+2)=3(y-1)+9 equation:

2(y+2)=3(y-1)+9

We move all terms to the left:

2(y+2)-(3(y-1)+9)=0

We multiply parentheses

2y-(3(y-1)+9)+4=0


We calculate terms in parentheses: -(3(y-1)+9), so:

3(y-1)+9

We multiply parentheses

3y-3+9

We add all the numbers together, and all the variables

3y+6

Back to the equation:

-(3y+6)


We get rid of parentheses

2y-3y-6+4=0

We add all the numbers together, and all the variables

-1y-2=0

We move all terms containing y to the left, all other terms to the right

-y=2

y=2/-1

y=-2