2(y+2)=4(y-2)-14

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Solution for 2(y+2)=4(y-2)-14 equation: 



2(y+2)=4(y-2)-14

We move all terms to the left:

2(y+2)-(4(y-2)-14)=0

We multiply parentheses

2y-(4(y-2)-14)+4=0



We calculate terms in parentheses: -(4(y-2)-14), so:

4(y-2)-14

We multiply parentheses

4y-8-14

We add all the numbers together, and all the variables

4y-22

Back to the equation:

-(4y-22)



We get rid of parentheses

2y-4y+22+4=0

We add all the numbers together, and all the variables

-2y+26=0

We move all terms containing y to the left, all other terms to the right

-2y=-26

y=-26/-2

y=+13

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