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2(y+2)=y+2+y
We move all terms to the left:
2(y+2)-(y+2+y)=0
We add all the numbers together, and all the variables
2(y+2)-(2y+2)=0
We multiply parentheses
2y-(2y+2)+4=0
We get rid of parentheses
2y-2y-2+4=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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