2(y+3)(y-3)=0

Solution for 2(y+3)(y-3)=0 equation:

Simplifying
2(y + 3)(y + -3) = 0

Reorder the terms:
2(3 + y)(y + -3) = 0

Reorder the terms:
2(3 + y)(-3 + y) = 0

Multiply (3 + y) * (-3 + y)
2(3(-3 + y) + y(-3 + y)) = 0
2((-3 * 3 + y * 3) + y(-3 + y)) = 0
2((-9 + 3y) + y(-3 + y)) = 0
2(-9 + 3y + (-3 * y + y * y)) = 0
2(-9 + 3y + (-3y + y2)) = 0

Combine like terms: 3y + -3y = 0
2(-9 + 0 + y2) = 0
2(-9 + y2) = 0
(-9 * 2 + y2 * 2) = 0
(-18 + 2y2) = 0

Solving
-18 + 2y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 2y2 = 0 + 18

Combine like terms: -18 + 18 = 0
0 + 2y2 = 0 + 18
2y2 = 0 + 18

Combine like terms: 0 + 18 = 18
2y2 = 18

Divide each side by '2'.
y2 = 9

Simplifying
y2 = 9

Take the square root of each side:
y = {-3, 3}