2(y+3)+2(3y+4)=70

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Solution for 2(y+3)+2(3y+4)=70 equation: 



2(y+3)+2(3y+4)=70

We move all terms to the left:

2(y+3)+2(3y+4)-(70)=0

We multiply parentheses

2y+6y+6+8-70=0

We add all the numbers together, and all the variables

8y-56=0

We move all terms containing y to the left, all other terms to the right

8y=56

y=56/8

y=7

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