2(y+3)+2y=4y+1

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Solution for 2(y+3)+2y=4y+1 equation: 



2(y+3)+2y=4y+1

We move all terms to the left:

2(y+3)+2y-(4y+1)=0

We add all the numbers together, and all the variables

2y+2(y+3)-(4y+1)=0

We multiply parentheses

2y+2y-(4y+1)+6=0

We get rid of parentheses

2y+2y-4y-1+6=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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