2(y+3)+3(y+1)=

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Solution for 2(y+3)+3(y+1)= equation:



2(y+3)+3(y+1)=
We move all terms to the left:
2(y+3)+3(y+1)-()=0
We add all the numbers together, and all the variables
2(y+3)+3(y+1)=0
We multiply parentheses
2y+3y+6+3=0
We add all the numbers together, and all the variables
5y+9=0
We move all terms containing y to the left, all other terms to the right
5y=-9
y=-9/5
y=-1+4/5

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