2(y+3)+3=31-3(y-1)

Solution for 2(y+3)+3=31-3(y-1) equation:

2(y+3)+3=31-3(y-1)

We move all terms to the left:

2(y+3)+3-(31-3(y-1))=0

We multiply parentheses

2y-(31-3(y-1))+6+3=0


We calculate terms in parentheses: -(31-3(y-1)), so:

31-3(y-1)

determiningTheFunctionDomain
-3(y-1)+31

We multiply parentheses

-3y+3+31

We add all the numbers together, and all the variables

-3y+34

Back to the equation:

-(-3y+34)


We add all the numbers together, and all the variables

2y-(-3y+34)+9=0

We get rid of parentheses

2y+3y-34+9=0

We add all the numbers together, and all the variables

5y-25=0

We move all terms containing y to the left, all other terms to the right

5y=25

y=25/5

y=5