2(y+3)+4y=3(y+1)+2

Solution for 2(y+3)+4y=3(y+1)+2 equation:

Simplifying
2(y + 3) + 4y = 3(y + 1) + 2

Reorder the terms:
2(3 + y) + 4y = 3(y + 1) + 2
(3 * 2 + y * 2) + 4y = 3(y + 1) + 2
(6 + 2y) + 4y = 3(y + 1) + 2

Combine like terms: 2y + 4y = 6y
6 + 6y = 3(y + 1) + 2

Reorder the terms:
6 + 6y = 3(1 + y) + 2
6 + 6y = (1 * 3 + y * 3) + 2
6 + 6y = (3 + 3y) + 2

Reorder the terms:
6 + 6y = 3 + 2 + 3y

Combine like terms: 3 + 2 = 5
6 + 6y = 5 + 3y

Solving
6 + 6y = 5 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
6 + 6y + -3y = 5 + 3y + -3y

Combine like terms: 6y + -3y = 3y
6 + 3y = 5 + 3y + -3y

Combine like terms: 3y + -3y = 0
6 + 3y = 5 + 0
6 + 3y = 5

Add '-6' to each side of the equation.
6 + -6 + 3y = 5 + -6

Combine like terms: 6 + -6 = 0
0 + 3y = 5 + -6
3y = 5 + -6

Combine like terms: 5 + -6 = -1
3y = -1

Divide each side by '3'.
y = -0.3333333333

Simplifying
y = -0.3333333333