2(y+3)+5(1-y)=7(2y+1)-3y

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Solution for 2(y+3)+5(1-y)=7(2y+1)-3y equation: 



2(y+3)+5(1-y)=7(2y+1)-3y

We move all terms to the left:

2(y+3)+5(1-y)-(7(2y+1)-3y)=0

We add all the numbers together, and all the variables

2(y+3)+5(-1y+1)-(7(2y+1)-3y)=0

We multiply parentheses

2y-5y-(7(2y+1)-3y)+6+5=0



We calculate terms in parentheses: -(7(2y+1)-3y), so:

7(2y+1)-3y

We add all the numbers together, and all the variables

-3y+7(2y+1)

We multiply parentheses

-3y+14y+7

We add all the numbers together, and all the variables

11y+7

Back to the equation:

-(11y+7)



We add all the numbers together, and all the variables

-3y-(11y+7)+11=0

We get rid of parentheses

-3y-11y-7+11=0

We add all the numbers together, and all the variables

-14y+4=0

We move all terms containing y to the left, all other terms to the right

-14y=-4

y=-4/-14

y=2/7

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