2(y+3)+5(y-4)+6=

Solution for 2(y+3)+5(y-4)+6= equation:

Simplifying
2(y + 3) + 5(y + -4) + 6 = 0

Reorder the terms:
2(3 + y) + 5(y + -4) + 6 = 0
(3 * 2 + y * 2) + 5(y + -4) + 6 = 0
(6 + 2y) + 5(y + -4) + 6 = 0

Reorder the terms:
6 + 2y + 5(-4 + y) + 6 = 0
6 + 2y + (-4 * 5 + y * 5) + 6 = 0
6 + 2y + (-20 + 5y) + 6 = 0

Reorder the terms:
6 + -20 + 6 + 2y + 5y = 0

Combine like terms: 6 + -20 = -14
-14 + 6 + 2y + 5y = 0

Combine like terms: -14 + 6 = -8
-8 + 2y + 5y = 0

Combine like terms: 2y + 5y = 7y
-8 + 7y = 0

Solving
-8 + 7y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 7y = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 7y = 0 + 8
7y = 0 + 8

Combine like terms: 0 + 8 = 8
7y = 8

Divide each side by '7'.
y = 1.142857143

Simplifying
y = 1.142857143