2(y+3)+7(y-4)+6=

Solution for 2(y+3)+7(y-4)+6= equation:

Simplifying
2(y + 3) + 7(y + -4) + 6 = 0

Reorder the terms:
2(3 + y) + 7(y + -4) + 6 = 0
(3 * 2 + y * 2) + 7(y + -4) + 6 = 0
(6 + 2y) + 7(y + -4) + 6 = 0

Reorder the terms:
6 + 2y + 7(-4 + y) + 6 = 0
6 + 2y + (-4 * 7 + y * 7) + 6 = 0
6 + 2y + (-28 + 7y) + 6 = 0

Reorder the terms:
6 + -28 + 6 + 2y + 7y = 0

Combine like terms: 6 + -28 = -22
-22 + 6 + 2y + 7y = 0

Combine like terms: -22 + 6 = -16
-16 + 2y + 7y = 0

Combine like terms: 2y + 7y = 9y
-16 + 9y = 0

Solving
-16 + 9y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 9y = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 9y = 0 + 16
9y = 0 + 16

Combine like terms: 0 + 16 = 16
9y = 16

Divide each side by '9'.
y = 1.777777778

Simplifying
y = 1.777777778