2(y+3)-3(y-4)=13

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Solution for 2(y+3)-3(y-4)=13 equation:



2(y+3)-3(y-4)=13
We move all terms to the left:
2(y+3)-3(y-4)-(13)=0
We multiply parentheses
2y-3y+6+12-13=0
We add all the numbers together, and all the variables
-1y+5=0
We move all terms containing y to the left, all other terms to the right
-y=-5
y=-5/-1
y=+5

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