2(y+3)-3y=8-2(2y-5)

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Solution for 2(y+3)-3y=8-2(2y-5) equation: 



2(y+3)-3y=8-2(2y-5)

We move all terms to the left:

2(y+3)-3y-(8-2(2y-5))=0

We add all the numbers together, and all the variables

-3y+2(y+3)-(8-2(2y-5))=0

We multiply parentheses

-3y+2y-(8-2(2y-5))+6=0



We calculate terms in parentheses: -(8-2(2y-5)), so:

8-2(2y-5)

determiningTheFunctionDomain
-2(2y-5)+8

We multiply parentheses

-4y+10+8

We add all the numbers together, and all the variables

-4y+18

Back to the equation:

-(-4y+18)



We add all the numbers together, and all the variables

-1y-(-4y+18)+6=0

We get rid of parentheses

-1y+4y-18+6=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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