2(y+3)-4=4y+12

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Solution for 2(y+3)-4=4y+12 equation: 



2(y+3)-4=4y+12

We move all terms to the left:

2(y+3)-4-(4y+12)=0

We multiply parentheses

2y-(4y+12)+6-4=0

We get rid of parentheses

2y-4y-12+6-4=0

We add all the numbers together, and all the variables

-2y-10=0

We move all terms containing y to the left, all other terms to the right

-2y=10

y=10/-2

y=-5

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