2(y+3)=-2y+6+4y,y=

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Solution for 2(y+3)=-2y+6+4y,y= equation: 



2(y+3)=-2y+6+4y.y=

We move all terms to the left:

2(y+3)-(-2y+6+4y.y)=0

We add all the numbers together, and all the variables

2(y+3)-(-2y+4y.y+6)=0

We multiply parentheses

2y-(-2y+4y.y+6)+6=0

We get rid of parentheses

2y+2y-4y.y-6+6=0

We add all the numbers together, and all the variables

4y-4y.y=0

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