2(y+3)=10+y

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Solution for 2(y+3)=10+y equation: 



2(y+3)=10+y

We move all terms to the left:

2(y+3)-(10+y)=0

We add all the numbers together, and all the variables

2(y+3)-(y+10)=0

We multiply parentheses

2y-(y+10)+6=0

We get rid of parentheses

2y-y-10+6=0

We add all the numbers together, and all the variables

y-4=0

We move all terms containing y to the left, all other terms to the right

y=4

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