2(y+3)=2(y-2)+10

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Solution for 2(y+3)=2(y-2)+10 equation: 



2(y+3)=2(y-2)+10

We move all terms to the left:

2(y+3)-(2(y-2)+10)=0

We multiply parentheses

2y-(2(y-2)+10)+6=0



We calculate terms in parentheses: -(2(y-2)+10), so:

2(y-2)+10

We multiply parentheses

2y-4+10

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

2y-2y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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