2(y+3)=3(y+4)+7

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Solution for 2(y+3)=3(y+4)+7 equation: 



2(y+3)=3(y+4)+7

We move all terms to the left:

2(y+3)-(3(y+4)+7)=0

We multiply parentheses

2y-(3(y+4)+7)+6=0



We calculate terms in parentheses: -(3(y+4)+7), so:

3(y+4)+7

We multiply parentheses

3y+12+7

We add all the numbers together, and all the variables

3y+19

Back to the equation:

-(3y+19)



We get rid of parentheses

2y-3y-19+6=0

We add all the numbers together, and all the variables

-1y-13=0

We move all terms containing y to the left, all other terms to the right

-y=13

y=13/-1

y=-13

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