2(y+3)=3(y+4)=7

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Solution for 2(y+3)=3(y+4)=7 equation: 



2(y+3)=3(y+4)=7

We move all terms to the left:

2(y+3)-(3(y+4))=0

We multiply parentheses

2y-(3(y+4))+6=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

2y-3y-12+6=0

We add all the numbers together, and all the variables

-1y-6=0

We move all terms containing y to the left, all other terms to the right

-y=6

y=6/-1

y=-6

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