2(y+3)=4y+5

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Solution for 2(y+3)=4y+5 equation: 



2(y+3)=4y+5

We move all terms to the left:

2(y+3)-(4y+5)=0

We multiply parentheses

2y-(4y+5)+6=0

We get rid of parentheses

2y-4y-5+6=0

We add all the numbers together, and all the variables

-2y+1=0

We move all terms containing y to the left, all other terms to the right

-2y=-1

y=-1/-2

y=1/2

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