2(y+30)=3y+12

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Solution for 2(y+30)=3y+12 equation: 



2(y+30)=3y+12

We move all terms to the left:

2(y+30)-(3y+12)=0

We multiply parentheses

2y-(3y+12)+60=0

We get rid of parentheses

2y-3y-12+60=0

We add all the numbers together, and all the variables

-1y+48=0

We move all terms containing y to the left, all other terms to the right

-y=-48

y=-48/-1

y=+48

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