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2(y+4)+3(y-10)=-6(y-4)+15
We move all terms to the left:
2(y+4)+3(y-10)-(-6(y-4)+15)=0
We multiply parentheses
2y+3y-(-6(y-4)+15)+8-30=0
We calculate terms in parentheses: -(-6(y-4)+15), so:We add all the numbers together, and all the variables
-6(y-4)+15
We multiply parentheses
-6y+24+15
We add all the numbers together, and all the variables
-6y+39
Back to the equation:
-(-6y+39)
5y-(-6y+39)-22=0
We get rid of parentheses
5y+6y-39-22=0
We add all the numbers together, and all the variables
11y-61=0
We move all terms containing y to the left, all other terms to the right
11y=61
y=61/11
y=5+6/11
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